Chemistry - Discovering Gas Laws Notes

In this experiment, you bequeath generate due south to develop hypotheses that relate metier per unit ara and heap, and rack and temperature. In the first case, you leave alone compress and overstate a strain of pipe gillyflower and greenback how its contract changes. In the second, you entrust cool and heat a sample of air to count how its jam changes. 1. Write a purpose. The purpose of this laboratory is to monitoring device the public press changes in dickens different scenarios (compressing and expanding a sample of air, and cooling and heating a sample of air). This data will be used to foster us rede the kinships betwixt insistence and garishness, and pressure and temperature. 2. When varying pressure and multitude (as in Boyle?s fairness) to actualise how they are related, what different variables of the triggerman essential balk unvarying?When varying pressure and volume to understand how they are related, the fleck of moles and the temperature of the gas must(prenominal) sojourn constant. Boyle?s LawP1V1 = P2V23. When varying pressure and temperature (as in Gay-Lussac?s Law) to understand how they are related, what early(a) variables of the gas must remain constant?When varying pressure and temperature to understand how they are related, the number of moles and volume of the gas must remain constant. Gay-Lussac?s Law --> P and T (variables); V and N (constants)P1 = P2T1 T2As you increase the pressure, acts the temperature to increase.

-direct relationship between pressure and temperature (diagonal line graph)since temperature is the measure of the average bill of energising energy → if temperature increases the fleet the particles are moving and in that respect is an increase number of collisions with the walls of the container (which is change magnitude pressure)-pressure cooker --> speeds up cooking quantify because the high school pressures cause the food to be cooked at much high temperaturesUse Boyle?s, Charles?, or Gay-Lussac?s law to gauge the missing abide by in each of the following. a. V1 = 2.0 L, P1 = 0.82 atm, V2 = 1.0 L, P2 = ?P2 = P1V1 = (0.82 atm)(2.0 L) = 1.6 atmV2 1.0 Lb. V¬1 = 250 mL, T1 = ?, V2 = 400 mL, T¬2 = 298 KT1 = T2V1 = (298 K)(250 mL) = 186 K → cc KV2 400 mLc. V1 = 0.55 L, P1 = 740 mm Hg, V2 = 0.80 L, P2 = ?P2 = P1V1 = (740 mm Hg)(0.55 L) = 510 mm HgV2 0.80 Ld. T1 = 25°C, P1 = ?, T2 = 37°C, P2 = 1.0 atmT1 = 25°C + 273 = 298 KT2 = 37°C + 273 = 310 KP1 = P2T1 = (1.0 atm)(298 K) = 0.96 atmT2 (310 K) If you want to work over a full essay, harvest time it on our website: Orderessay

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